Asked by Anonymous
Find the area underneath the curve of y= sin(x/2) from 0 to 3π/4 show your graph as well.
Answers
Answered by
oobleck
∫[0,3π/4] sin(x/2) = -2cos(x/2) [0,3π/4]
= -2(cos(3π/8) - cos(0))
= 2(1 - cos(π/8))
= 2(1 - √(2+√2)/2)
= 2 - √(2+√2)
= -2(cos(3π/8) - cos(0))
= 2(1 - cos(π/8))
= 2(1 - √(2+√2)/2)
= 2 - √(2+√2)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.