Asked by Zainab

A body vibrates in simple harmonic motion with the frequency of 50hz and amplitude of 4cm, find period, acceleration at the middle and the end of the path of oscillation.

Answers

Answered by Zainab
I need the solution
Answered by Anonymous
period is 1/f = 0.02
y = 0.04 sin (2 pi f t) = 0.04 sin (100 pi t)
v = 0.04 (100 pi) cos (100 pi t)
a = -0.04 (100 pi)^2 sin (100 pi t) = - (100 pi)^2 y so acceleration at middle is zero:) and at max is 0.04 (100 pi)^2
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions