The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force

Ft
and the force
Fs
which hold the arm in equilibrium. (Let 𝜃 = 23.5°.) Assume the weight of the arm is 48.7 N.

An arm is extending horizontally to the right with a cutout that shows muscles in the upper arm. A horizontal dashed line extends along the bottom of the muscles and another along the top. Point O is labeled at the left end of the arm on the lower horizontal line. An unlabeled point lies 8.00 cm horizontally to the right of point O. Point A lies 29.0 cm horizontally to the right of point O. Three forces are acting on the arm.
A force vector Fs acts down and right on point O.
A force vector Ft acts up and left on the unlabeled point at an acute angle 𝜃 above the horizontal. Vector Ft is longer than vector Fs.
A force vector Fg acts vertically down on point A. Vector Fg is shorter than vector Fs.