Asked by Starsky

Find the positive root of 2x^2-5x-5=0
Answered by Damon
[-5 +/- sqrt(25 + 40) ] / 4

(1/4)(-5 + sqrt(65) )

(1/4)(-5+8.06)
(1/4)(3.06) = .766

Answered by Starsky
I meant to put 2x^2-5x-3=0
Answered by Damon
(x-3)(2x+1) = 0
x = 3 since x = -1/2 is negative
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