Asked by samsam
A bob attached to a string of length L = 1.25 m, initially found at the equilibrium position, is given an initial velocity v = 0.8 m/s. The maximum displacement angle, θmax, is: (Take g=10 m/s²)
Answers
Answered by
oobleck
the max height reached is when all the KE is converted to PE, so
v^2 = 2gh
h = 0.8^2/20 = 0.032 m
cosθ = (1.25-0.032)/1.25 = 0.9744
θ = 13°
v^2 = 2gh
h = 0.8^2/20 = 0.032 m
cosθ = (1.25-0.032)/1.25 = 0.9744
θ = 13°
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.