Asked by Abed
A block attached to a spring oscillates in simple harmonic motion along the x-axis between the two extremes, x = 10 cm and x = 30 cm. The block goes from one extreme to the other in 0.25 s. Its amplitude and frequency are:
Answers
Answered by
oobleck
A = (30-10)/2 = 10 cm
the period is 2*.25 = .5 s
f = 1/.5s = 2 Hz
the period is 2*.25 = .5 s
f = 1/.5s = 2 Hz
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