Question

A two man bobsled is pushed along a horizontal, frictionless track by the brakeman. The driver and
bobsled have a mass of 280 kg. The brakeman pushes with a net force of 160 N a distance of 50
m. What is the final speed of the bobsled just before the brakeman jumps into the sled? The sled
was pushed for 6.61 s. How much power does the brakeman expend on the sled?

Answer 1

v^2 = 2as = 2(160/280)(50) = 57.14
so v = 7.56 m/s

power = force*distance/time
so plug in your numbers