Asked by caramelmachiato
                A particle moves along a coordinate axis in such a way that its position at time t is given by 
s(t)=(√(3t))+2cos(t) for 0≤t≤2π . At what time is the particle at rest?
            
        s(t)=(√(3t))+2cos(t) for 0≤t≤2π . At what time is the particle at rest?
Answers
                    Answered by
            oobleck
            
    it is at rest when s'(t) = 0 . That is, when
3/(2√(3t)) - 2sin(t) = 0
t = 0.5957, 2.8838
    
3/(2√(3t)) - 2sin(t) = 0
t = 0.5957, 2.8838
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.