Asked by caramelmachiato
A particle moves along a coordinate axis in such a way that its position at time t is given by
s(t)=(√(3t))+2cos(t) for 0≤t≤2π . At what time is the particle at rest?
s(t)=(√(3t))+2cos(t) for 0≤t≤2π . At what time is the particle at rest?
Answers
Answered by
oobleck
it is at rest when s'(t) = 0 . That is, when
3/(2√(3t)) - 2sin(t) = 0
t = 0.5957, 2.8838
3/(2√(3t)) - 2sin(t) = 0
t = 0.5957, 2.8838
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