Question

the combustion of a sample of butane, C4H10 (lighter fluid) produced 3.75 moles of water.

how to solve for: (with solution)
1.) how many grams of butane burned?
2.) How much oxygen was used up in grams?
(1) the reaction equation will tell you how many moles of butane to use -- convert to grams
(2) again, consult the equation and convert moles to grams

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How many butane molecules are present in a sample that contains 5.0 moles of butane? (Butane- C4H10)... The balanced equation for the combustion of butane, C4H10, is 2 C4H10(g) + 13 O2(g) → 8 CO2(g) +... . Butane C4H10 undergoes combustion in the following reaction: 2 C4H10 + 13 O2 8 CO2 + 10 H2O In... Butane (C4H10) burns in the presence of oxygen (O2) to produce carbon dioxide (CO2) and water (H2O)....