Asked by London
Given y'=16/x with y(e)=29. Find y(e^2)
Answers
Answered by
oobleck
dy/dx = 16/x
y = 16 lnx + c
29 = 16 lne + c
c = 13
y = 16 lnx + 13
y(e^2) = 16*2 + 13 = ____
y = 16 lnx + c
29 = 16 lne + c
c = 13
y = 16 lnx + 13
y(e^2) = 16*2 + 13 = ____
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