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Asked by Stephanie

Find the exact value of cotθ given secθ=3 and tanθ<0.

cotθ=8√/3
cotθ=−(3/√8)
cotθ=1/√8
cotθ=−(√8/3)
cotθ=−√8
cotθ=3/√8
cotθ=−(1/√8)
cotθ=√8


Is it cotθ=−(1/√8)?

thanks
3 years ago

Answers

Answered by Anonymous
cos =1/3 so positive x
cos/sin = negative so y is negative, quadrant 4
sin = - sqrt 8 / 3
cot = cos/sin= (1/3) / (- sqrt 8 /3) = -1 / sqrt 8
so yes
3 years ago
Answered by Anonymous
by the way sqrt 8 = 2 sqrt 2
3 years ago
Answered by oobleck
correct
3 years ago

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