Asked by Stephanie
Find the exact value of cotθ given secθ=3 and tanθ<0.
cotθ=8√/3
cotθ=−(3/√8)
cotθ=1/√8
cotθ=−(√8/3)
cotθ=−√8
cotθ=3/√8
cotθ=−(1/√8)
cotθ=√8
Is it cotθ=−(1/√8)?
thanks
cotθ=8√/3
cotθ=−(3/√8)
cotθ=1/√8
cotθ=−(√8/3)
cotθ=−√8
cotθ=3/√8
cotθ=−(1/√8)
cotθ=√8
Is it cotθ=−(1/√8)?
thanks