Asked by I need help pls
Solve by substitution:
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
-x-y-z=-8
-4x+4y+5z=7
2x+2z=4
Answers
Answered by
Anonymous
multiply the first one by - 2
2 x + 2 y + 2 z = 16
from the last one substitute 4 for 2x+2z
2 y + 4 = 16
y = 12/2 = 6
now go back for the rest :)
2 x + 2 y + 2 z = 16
from the last one substitute 4 for 2x+2z
2 y + 4 = 16
y = 12/2 = 6
now go back for the rest :)
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