Question

MgCl2 + AgOH will produce?
and it's net chemical equation.

Answer 1

MgCl2 + AgOH is interesting. I suspect the author of the problem is thinking
MgCl2 + 2AgOH ==> Mg(OH)2(s) + 2AgCl(s) and the net ionic equation is
Mg^2+ + 2Cl^- + 2Ag^+ + 2OH^- --> Mg(OH)2(s) + 2AgCl(s)
However, I don't think this will happen. First, the Ksp for Ag(OH)2 is 2E-8 so the solubility is 1.4E-4M and the product Mg(OH)2 is 1.2E-4M so the driving force for this reaction just isn't there. In addition the AgOH isn't soluble enough initially to produce enough OH^- to ppt Mg(OH)2. It is helped slightly since AgCl is 1E-5M. Complicating matters is the fact that AgOH isn't stable in water and forms Ag2O which is very insoluble. So you are likely to get a complicated set up with Ag2O and slight amounts of AgCl and Mg(OH)2. I know this is not the answer you want. If this is a beginning class in chemistry then I would write the molecular equation as
MgCl2(aq) + AgOH(s) ==> Mg(OH)2(s) + 2AgCl(s) and the resulting net ionic equation is impossible to write. This question has no simple answer.