Question

A 0.394 gram sample of KHC8H4O4 is dissolved in 100 ml of water. If 13.9 mL of NaOH solution are required to reach the equivalence point, what is the normality of the NaOH? KHC8H4O4's equivalent weight is 204.2 g/equiv
The following equation will work almost all or part of your normality problems
mL x N x milliequivalent weight (mew) = grams
13.9 mL x N x 0.2042 mew = 0.394 g

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