Asked by Anonymous
Determine the mass of carbon dioxide (in g) produced from the complete combustion of 512.1 g of C8H18 with excess oxygen. Report your answer to the proper number of significant digits without units.
Answers
Answered by
DrBob222
Write this down. It will solve all of them.
Step 1. Write and balance the equation.
2C8H18 + 25O2 ==> 16CO2 + 18H2O
Step 2. Convert what you have (in this case C8H18) into moles.
moles = g/molar mass = 512.1/114.23 = 4.4831
Step 3. Convert moles of what you have (C8H18) into moles of what you want (CO2) by using the coefficients in the balanced equation.
4.4831 mols C8H18 x (16 moles CO2/2 mols C8H18) = 4.4831 x 16/2 = 35.864 moles CO2.
Step 4. Now convert moles to grams.
g CO2 = mols CO2 x molar mass CO2 = ?. Then round the answer to 4 digits.
Post your work if you get stuck. Keep this post handy. It will take care of all of the stoichiometry problems you may have. Use this as a template for other stoichiometry problem.
Step 1. Write and balance the equation.
2C8H18 + 25O2 ==> 16CO2 + 18H2O
Step 2. Convert what you have (in this case C8H18) into moles.
moles = g/molar mass = 512.1/114.23 = 4.4831
Step 3. Convert moles of what you have (C8H18) into moles of what you want (CO2) by using the coefficients in the balanced equation.
4.4831 mols C8H18 x (16 moles CO2/2 mols C8H18) = 4.4831 x 16/2 = 35.864 moles CO2.
Step 4. Now convert moles to grams.
g CO2 = mols CO2 x molar mass CO2 = ?. Then round the answer to 4 digits.
Post your work if you get stuck. Keep this post handy. It will take care of all of the stoichiometry problems you may have. Use this as a template for other stoichiometry problem.
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