Question
A 2.0 kg block compresses a 0.50 m from its equilibrium length. The mass is released and slides along a frictionless surface .When it has just lost contact with the spring its speed is measured to be 5.0 m/s. find the spring constant.
Answers
oobleck
on launch, its KE = 1/2 mv^2
That is the PE in the spring when it was compressed.
PE = 1/2 kx^2
So now plug in your numbers to find k.
That is the PE in the spring when it was compressed.
PE = 1/2 kx^2
So now plug in your numbers to find k.