Asked by Rachel
                Find the exact solution and estimated solution to the equation using natural logarithms. If there is no solution, enter DNE in all capital letters. If there is just one solution, enter DNE in all capital letters in one of the answer boxes. Round the estimated answer to three decimal places.
e^2x−2e^x−24=0
Exact Solution: x= ln(6), DNE correct
but for
estimation I got x=1.79175....and I don't know what to put in the second box
            
        e^2x−2e^x−24=0
Exact Solution: x= ln(6), DNE correct
but for
estimation I got x=1.79175....and I don't know what to put in the second box
Answers
                    Answered by
            oobleck
            
    e^2x−2e^x−24=0
(e^x - 6)(x^x + 4)
so, yes, ln6 is the exact solution
2nd box must still be DNE
    
(e^x - 6)(x^x + 4)
so, yes, ln6 is the exact solution
2nd box must still be DNE
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