Asked by Emmanuel
The distance of a port from 20 different locations form an AP.if the farthest distance is 300km, and the nearest distance is 30km, what is the distance between any two successive locations?
Answers
Answered by
Bosnian
In this A.P. distances are:
a , a + r , a + 2 r ... , a + 19 r
where a is the distance of the nearest location from the port and r is the difference between any two successive location.
In this case a =30 km
The farthest distance is 300 km
The farthest distance is 20th term of A.P.
a20 = a + 19 r
a + 19 r = 300
30 + 19 r = 300
19 r = 300 - 30
r = 270 /19 km
270 / 19 km is the distance between any two successive location.
a , a + r , a + 2 r ... , a + 19 r
where a is the distance of the nearest location from the port and r is the difference between any two successive location.
In this case a =30 km
The farthest distance is 300 km
The farthest distance is 20th term of A.P.
a20 = a + 19 r
a + 19 r = 300
30 + 19 r = 300
19 r = 300 - 30
r = 270 /19 km
270 / 19 km is the distance between any two successive location.
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