Question

The distance of a port from 20 different locations form an AP.if the farthest distance is 300km, and the nearest distance is 30km, what is the distance between any two successive locations?

Answers

In this A.P. distances are:

a , a + r , a + 2 r ... , a + 19 r

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

In this case a =30 km

The farthest distance is 300 km

The farthest distance is 20th term of A.P.

a20 = a + 19 r

a + 19 r = 300

30 + 19 r = 300

19 r = 300 - 30

r = 270 /19 km

270 / 19 km is the distance between any two successive location.

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