Asked by Ricky

given that x^2+2mx+m^2-2m+3=0 has 2 roots a and B (with a<B)
1. Find a+B and aB in terms of m
2. Find (a-b)^2 in terms of m
3. If B-a=2, find m
Answered by oobleck
a+b = -2m
ab = (m^2-2m+3)

(a-b)^2 = (a+b)^2 - 4ab

now finish it off
Answered by Hh
I recommend asking your parents
Answered by Ricky
oobleck how about number 3?
Answered by Ricky
Hh, I don't have my parents with me.
They are with you.
Answered by Mika
oobleck is it 8m-12
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