Asked by Mesha
Joe and Jerry went for a bike trek during the holidays. On the first day they rode 1/3 of the total distance. On the second day they were tired and only rode 25% of the remaining distance. Last day they rode the remaining 18 km. Calculate the
Answers
Answered by
oobleck
1/3 x + 0.25(2/3 x) + 18 = x
now finish it off
now finish it off
Answered by
Husayn Zahr
72km
Answered by
Bot
To solve for x, we first need to combine the two fractions on the right-hand side:
1/3 x + 0.25(2/3 x) = 1/3 x + 1/6 x = 1/2 x
So now we have:
1/2 x + 18 = x
Subtracting 1/2 x from both sides, we get:
18 = 1/2 x
Multiplying both sides by 2, we get:
x = 36
Therefore, the total distance of the bike trek was 36 km + 18 km (from the last day) = 54 km.
However, the question asks us to calculate the distance they rode on the second day, which was 25% of the remaining distance after the first day.
On the first day they rode 1/3 of the total distance, which is:
(1/3) * 54 km = 18 km
So after the first day, the remaining distance was:
54 km - 18 km = 36 km
And on the second day, they rode:
0.25 * 36 km = 9 km
Therefore, Joe and Jerry rode 9 km on the second day.
1/3 x + 0.25(2/3 x) = 1/3 x + 1/6 x = 1/2 x
So now we have:
1/2 x + 18 = x
Subtracting 1/2 x from both sides, we get:
18 = 1/2 x
Multiplying both sides by 2, we get:
x = 36
Therefore, the total distance of the bike trek was 36 km + 18 km (from the last day) = 54 km.
However, the question asks us to calculate the distance they rode on the second day, which was 25% of the remaining distance after the first day.
On the first day they rode 1/3 of the total distance, which is:
(1/3) * 54 km = 18 km
So after the first day, the remaining distance was:
54 km - 18 km = 36 km
And on the second day, they rode:
0.25 * 36 km = 9 km
Therefore, Joe and Jerry rode 9 km on the second day.
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