solve the following equations for real X and Y
1) (2-3i) (x+yi) = 4+i
2) (2-2i) (x+yi) = 2(x=2yi) + 2i - 1
need help :( after getting answer i m gonna write this mathematics in my death note lol
1) (2-3i) (x+yi) = 4+i
2) (2-2i) (x+yi) = 2(x=2yi) + 2i - 1
need help :( after getting answer i m gonna write this mathematics in my death note lol
Answers
Answered by
Jeon Jungkook
6 views!! but still no one answer ...-_-!
Answered by
oobleck
impatient much? whining after 10 minutes?
Have you been working on it while waiting for someone to help?
Two complex numbers are equal if their real and imaginary parts are equal
(2-3i) (x+yi) = 4+i
2x - 3xi + 2yi + 3y = 4+i
(2x+3y) + (-3x+2y) = 4+i
That means that
2x+3y = 4
-3x+2y = 1
x = 5/13 and y = 14/13
check: (2-3i)(5+14i)/13 = 4+i yes
assuming a typo, I used
(2-2i) (x+yi) = 2(x+2yi) + 2i - 1
(2x+2y) + (-2x+2y)i = (2x-1) + (4y+2)i
so now just solve
2x+2y = 2x-1
-2x+2y = 4y+2
Have you been working on it while waiting for someone to help?
Two complex numbers are equal if their real and imaginary parts are equal
(2-3i) (x+yi) = 4+i
2x - 3xi + 2yi + 3y = 4+i
(2x+3y) + (-3x+2y) = 4+i
That means that
2x+3y = 4
-3x+2y = 1
x = 5/13 and y = 14/13
check: (2-3i)(5+14i)/13 = 4+i yes
assuming a typo, I used
(2-2i) (x+yi) = 2(x+2yi) + 2i - 1
(2x+2y) + (-2x+2y)i = (2x-1) + (4y+2)i
so now just solve
2x+2y = 2x-1
-2x+2y = 4y+2
Answered by
Jeon Jungkook
No, that's what I was doing
i was trying to solve this and i got right answer
by the way thank you for your help :)
i was trying to solve this and i got right answer
by the way thank you for your help :)
Answered by
Jeon Jungkook
by the way are you teacher?
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