Two forces F1 = (62.13i − 54.63j) N and F2 = (19.73i − 69.15j) N are exerted on a particle. The particle's mass is 11.30 kg.

(a) Find the particle's acceleration in component form. (Express your answer in vector form.)
(b) Find the magnitude and direction of the acceleration (degree counterclockwise from the x axis)

1 answer

for each F, extract the components
add them up to get the resultant force
F = ma
Now, having a,
(b) get |a|
the direction is tanθ = y/x (from a)
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