Asked by Anonymous
At atmospheric pressure of 1 atm, the partial pressure of oxygen in air is 0.21 atm. At this atmospheric pressure and 25°C, water contains 2.73 x 10^-4 M dissolved oxygen gas. What is the Henry's Law constant for oxygen dissolved water at this temperature in terms of M and atm?
Answers
Answered by
DrBob222
H = c/p = 2.73E-4/0.21 = ?
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