Asked by Anonymous
                Which of the following pairs is correct (for the correct reason) regarding the ionization energy of the atoms? *
A.Na < P; ionization energy increases across a period
B.Na > Al; increasing number of electron shells in Al
C.N < Bi; metals are higher than nonmetals
D.N > O; increasing electron repulsion in p sublevel
            
        A.Na < P; ionization energy increases across a period
B.Na > Al; increasing number of electron shells in Al
C.N < Bi; metals are higher than nonmetals
D.N > O; increasing electron repulsion in p sublevel
Answers
                    Answered by
            DrBob222
            
    So which did you pick. I would go with a. One thing the question is not clear about......For Na, for example, that obviously is for removing the one outside shell electron but for P, which has an outside shell of 5 electrons (3s2 3p3), is that removing 1 or more 3p electrons or all 5 outside shell electrons. What I mean by that is that P has five ionization energies depending upon how many of those electrons are removed 
    
                    Answered by
            Anonymous
            
    Thank you! A is the one I pick.
    
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