Asked by I am confused
Find the indicated ouputs:
f(n)=2^n a. f(5)= b. f(0)=
f(n)=5^n a. f(4)= b. f(1)=
f(n)=(-2)^n a. f(3)= b. f(0)=
f(n)= -2^n a. f(3)= b. f(0)=
I am so confused because my teacher didn't explain what these are please help :(
f(n)=2^n a. f(5)= b. f(0)=
f(n)=5^n a. f(4)= b. f(1)=
f(n)=(-2)^n a. f(3)= b. f(0)=
f(n)= -2^n a. f(3)= b. f(0)=
I am so confused because my teacher didn't explain what these are please help :(
Answers
Answered by
oobleck
the "n" is just a place holder. You can replace it with whatever you want.
f(n) = 2^n, so f(5) = 2^5 = 32
f(n) = (-2)^n so f(3) = (-2)^3 = (-2)(-2)(-2) = -8
f(0) = (-2)^0 = 1
anything (except 0) to the zero power is 1
f(n) = -2^n
since powers are done before subtraction (PEMDAS)
f(3) = -2^3 = -(2^3) = -8
f(0) = -(2^0) = -1
f(n) = 2^n, so f(5) = 2^5 = 32
f(n) = (-2)^n so f(3) = (-2)^3 = (-2)(-2)(-2) = -8
f(0) = (-2)^0 = 1
anything (except 0) to the zero power is 1
f(n) = -2^n
since powers are done before subtraction (PEMDAS)
f(3) = -2^3 = -(2^3) = -8
f(0) = -(2^0) = -1
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