I t is originally 90+45 = 135 deg cc from the x axis
spin 270 more ----> 405 total
405 - 360 = 45
so 45 degrees above x axis in quadrant 1
(6, 6)
The point Z(–6,6) is rotated 270° counterclockwise around the origin. What are the coordinates of the resulting point, Z
4 answers
The point C(4,5) is rotated 270° counterclockwise around the origin. What are the coordinates of the resulting point, C'?
Ver en español
The point J(
–
2,2) is rotated 270° clockwise around the origin. What are the coordinates of the resulting point, J'?
The point J(
–
2,2) is rotated 270° clockwise around the origin. What are the coordinates of the resulting point, J'?
When a point is rotated 270° clockwise, it is the same as rotating 90° counterclockwise.
To rotate a point 90° counterclockwise around the origin, you first swap the x and y coordinates and then negate the new x coordinate.
So, for point J(-2,2), we swap the coordinates to get (2,-2) and then negate the x-coordinate to get (-2,-2).
Therefore, the coordinates of the resulting point J' are (-2,-2).
To rotate a point 90° counterclockwise around the origin, you first swap the x and y coordinates and then negate the new x coordinate.
So, for point J(-2,2), we swap the coordinates to get (2,-2) and then negate the x-coordinate to get (-2,-2).
Therefore, the coordinates of the resulting point J' are (-2,-2).