Question

calculate the change in entropy when liquid mercury is vaporized.
Hg(l) = 75.9 J/mol K Hg(g) = 175.0 J/mol K

Answer 1

Hg(l) + heat ==> Hg(g)
dSrxn = dS(products) - dS(reactants)
dSrxn = (1 mol Hg(g) x 175.0 J/mol*K) - (1 mol Hg(l) x 75.9 J/mol*K) = ?