Asked by Channel
Please can you help me answer there questions? You have to do the sum's in the bracet's first.
2 (4a+7)
3 (2f+B)
5 (7+2x)
6 (2b-6)
12(6q-4)
Thank's for helping!
2 (4a+7)
3 (2f+B)
5 (7+2x)
6 (2b-6)
12(6q-4)
Thank's for helping!
Answers
Answered by
PsyDAG
2(4a + 7) = 8a + 14
Just multiply both terms within the parenthesis by the number in front of the parenthesis.
I hope this helps. If not, repost in more specific terms. Thanks for asking.
Just multiply both terms within the parenthesis by the number in front of the parenthesis.
I hope this helps. If not, repost in more specific terms. Thanks for asking.
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