Asked by Eli
3 to the power of y add 3 to the power of y add 3 to the power of y= 3 to the power of y+1. Why? (Sorry I couldn’t put the indices and had to write in words my keyboard didn’t let me)
Answers
Answered by
PsyDAG
It would help if you would proofread your work before you post it.
3 to the power of y = 3^y
Cannot make sense of your post.
3 to the power of y = 3^y
Cannot make sense of your post.
Answered by
oobleck
assuming no useless repetitions, we apparently have
3^(y+3)^(y+3)^y = 3^(y+1)
now, since exponents associate right-to-left, that's a monster. However, if your words allow us to use left-to-right association, then
((3^(y+3))^(y+3))^y = 3^(y+1)
(3^(y+3))^(y^2+3y) = 3^(y+1)
3^(y^3+6y^2+9y) = 3^(y+1)
y^3+6y^2+9y = y+1
y^3+6y^2+8y-1 = 0
That has no rational roots. So maybe you cab rewrite your problem, keeping in mind the rules of exponents.
3^(y+3)^(y+3)^y = 3^(y+1)
now, since exponents associate right-to-left, that's a monster. However, if your words allow us to use left-to-right association, then
((3^(y+3))^(y+3))^y = 3^(y+1)
(3^(y+3))^(y^2+3y) = 3^(y+1)
3^(y^3+6y^2+9y) = 3^(y+1)
y^3+6y^2+9y = y+1
y^3+6y^2+8y-1 = 0
That has no rational roots. So maybe you cab rewrite your problem, keeping in mind the rules of exponents.
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