Asked by Cagan
A person fires an arrow at 46.9 m/s at a nearby target some distance away. The sound of the arrow striking the target returns to the person at a rate of 321.8 m/s. If the total elapsed time between the release of the arrow and the person hearing the thud of the arrow is 2.24 seconds, what is the distance between the person and the target in meters?
Answers
Answered by
Cagan
Help a homie out guys
Answered by
Anonymous
distance to target = d
arrow speed = 46.9 m/s
time arrow to target = d/46.9
speed sound back = 321.8 m/s
time sound coming back = d/321.8
so
2.24 = d/46.9 + d/321.8
your turn now.
arrow speed = 46.9 m/s
time arrow to target = d/46.9
speed sound back = 321.8 m/s
time sound coming back = d/321.8
so
2.24 = d/46.9 + d/321.8
your turn now.
Answered by
Cagan
Thanks a lot dude!
Answered by
Cagan
I just didn't know how to get started
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