Asked by Trevor
A correct answer will yield me an "A" all SEMESTER, so help is appreciated
Question:
Can you find a pythagorean triple whose nonhypotunese legs aren't divisible by 12? Whatever the answer, yes or no, it must be proven.
Question:
Can you find a pythagorean triple whose nonhypotunese legs aren't divisible by 12? Whatever the answer, yes or no, it must be proven.
Answers
Answered by
Reiny
Wow, if this simple question yields an A for the semester, the course must have rather low expectations.
anyway....
the simplest Pythagorean triple is 3,4,5
so just multiply those values by a multiple of 12,
so 36,48,60
Verification 36^ + 48^2 = 60^2
or the triple 5,12, 13 would also do it
5^2 + 12^ = 13^2
there is an infinite number of triples for your answer.
anyway....
the simplest Pythagorean triple is 3,4,5
so just multiply those values by a multiple of 12,
so 36,48,60
Verification 36^ + 48^2 = 60^2
or the triple 5,12, 13 would also do it
5^2 + 12^ = 13^2
there is an infinite number of triples for your answer.
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