Asked by Sydney
A placekicker must kick a football from a point 36.0 m (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 24.0 m/s at an angle of 51.0° to the horizontal.
(a) By how much does the ball clear or fall short of clearing the crossbar? (Enter a negative answer if it falls short.)
m
(b) Does the ball approach the crossbar while still rising or while falling?
rising
falling
(a) By how much does the ball clear or fall short of clearing the crossbar? (Enter a negative answer if it falls short.)
m
(b) Does the ball approach the crossbar while still rising or while falling?
rising
falling
Answers
Answered by
Anonymous
u = horizontal speed forever = 24 cos 51 = 15.1 m/s
v = vertical speed = 24 sin 51 - 9.81 t = 18.7 - 9.81 t
x = horizontal distance = 15.1 t
y = height = 18.7 t - 4.9 t^2
so
a)
time at crossbar = 36.0 / 15.1 = 2.38 seconds
height at crossbar = 18.7 (2.38) - 4.9 (2.38)^2 = 44.5 - 27.8 = 16.7 meters
so 16.7 - 3.05
v = vertical speed = 24 sin 51 - 9.81 t = 18.7 - 9.81 t
x = horizontal distance = 15.1 t
y = height = 18.7 t - 4.9 t^2
so
a)
time at crossbar = 36.0 / 15.1 = 2.38 seconds
height at crossbar = 18.7 (2.38) - 4.9 (2.38)^2 = 44.5 - 27.8 = 16.7 meters
so 16.7 - 3.05
Answered by
Anonymous
b) when is the vertical speed = 0?
v= 18.7 -9.81 t
so t at top = 1.9 seconds
but it takes 2.38 seconds to reach crossbar
so it is on the way down
v= 18.7 -9.81 t
so t at top = 1.9 seconds
but it takes 2.38 seconds to reach crossbar
so it is on the way down
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.