Asked by Aida
4OH + Zn+Cu(OH)2→ [Zn(OH)4]2- + Cu + 2OH
how to balanced both side?
how to balanced both side?
Answers
Answered by
DrBob222
4OH + Zn+Cu(OH)2→ [Zn(OH)4]2- + Cu + 2OH
Start by removing the coefficients AND the right hand OH^- AND adding charges like this.
OH^- + Zn + Cu(OH)2→ [Zn(OH)4]^2- + Cu, then
2OH^- + Zn + Cu(OH)2→ [Zn(OH)4]^2- + Cu
Start by removing the coefficients AND the right hand OH^- AND adding charges like this.
OH^- + Zn + Cu(OH)2→ [Zn(OH)4]^2- + Cu, then
2OH^- + Zn + Cu(OH)2→ [Zn(OH)4]^2- + Cu
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