Asked by Ed
Suppose(8,6) is a point on the graph of y=g(x).
(b) What point is on the graph of y=-4g(x-4)+2?
I just know you go up 2 and right 4 but I don't know what to do with the -4 and if you could show me so I can understand the other problems! I kind of forgot about transformations
(b) What point is on the graph of y=-4g(x-4)+2?
I just know you go up 2 and right 4 but I don't know what to do with the -4 and if you could show me so I can understand the other problems! I kind of forgot about transformations
Answers
Answered by
oobleck
shift right 4
stretch by 4 vertically
reflect across the x-axis
shift up 2
(x,y) → (x+4,y) → (x+4,4y) → (x+4,-4y) → (x+4,-4y+2)
so (8,6) → (12,-22)
consider g(x) = x/2 + 2
the transformed function g'(x) = -4((x-4)/2 + 2)+2
g'(12) = -4(4+2)+2 = -22
stretch by 4 vertically
reflect across the x-axis
shift up 2
(x,y) → (x+4,y) → (x+4,4y) → (x+4,-4y) → (x+4,-4y+2)
so (8,6) → (12,-22)
consider g(x) = x/2 + 2
the transformed function g'(x) = -4((x-4)/2 + 2)+2
g'(12) = -4(4+2)+2 = -22
Answered by
Anonymous
Suppose is a point on the graph of yg(x).
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(b) What point is on the graph of ?
(c) What point is on the graph of ?
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