ABX + CBX = 92º
ABX = 4 CBX + 12º
substituting ... 5 CBX + 12º = 92º
solve for CBX , then substitute back to find ABX
In ∠ABC, BX−→− is in the interior of the angle, m∠ABX is 12 more than 4 times m∠CBX, and m∠ABC=92°
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