1.38g Mg = 0.051 moles
25mL * 2.0 M = 0.05 moles HCl
So it looks like only 0.025 moles of H2 will be released
1 moles occupies 22.4 L, so you will get 0.025 * 22.4 = ___ L of H2
When 1.38 g of magnesium is added to 25 mL of 2.0 M hydrochloric acid, hydrogen
gas is released according to the equation below:
Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)
Calculate the volume of the gas formed at STP
1 answer