Asked by hey
Three points P(-2,1), Q(-6,4), and R(4,3) are three vertices of a parallelogram PQRS. Use your knowledge on the magnitude of vectors to find a possible coordinate for S.
Answers
Answered by
oobleck
PQ = Q-P = -4i+3j
QR = R-Q = 10i-j
so, since
|PS| = |QR| and PS||QR,
S-P = 10i-j
S = P+R-Q = (-2,1)+(10,-1) = (8,0)
another arrangement gives S = (0,6)
QR = R-Q = 10i-j
so, since
|PS| = |QR| and PS||QR,
S-P = 10i-j
S = P+R-Q = (-2,1)+(10,-1) = (8,0)
another arrangement gives S = (0,6)
Answered by
hey
oh thank you! but what would be the other arrangement that would give (0,6), i think that's the one they're looking for
Answered by
oobleck
If you order the vertices PRQS you get (0,6)
Plot the points to see this.
Plot the points to see this.
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