Asked by Anonymous
Find the value of k for which 3x - y - 5 = 0 and 6x - 2y - k = 0 have infi nitely many solutions
Answers
Answered by
4TheLoveOfPhysics
Infinite solutions just means same equation.
Set up each equation in the form of y = mx + b:
1) y = 3x - 5
2) y = 3x - k/2
For the same equation, k/2 must equal 5.
k/2 = 5
Therefore, k = 10
Set up each equation in the form of y = mx + b:
1) y = 3x - 5
2) y = 3x - k/2
For the same equation, k/2 must equal 5.
k/2 = 5
Therefore, k = 10
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