Asked by Jackson silah
With aim of diagram construct a triangle ABC in which AB=5cm,BC=6cm and angle ABC=120 measure angle ACB,drop a perpendicular from C to cut AB produced at P.Measure CP.
Answers
Answered by
oobleck
It's easy to construct ABC.
Draw AB of length 5
Construct angle ABC (it's just two adjoining 60° angles)
with center at B, draw a circle of radius 6.
Mark C where the circle intersects ray BC.
So now produce AB to P and construct a ⊥ from C to P.
Measure CP
To confirm your answer, it is clear that angle BCP = 60°
So CP = 6 sin60° = 3√3
Draw AB of length 5
Construct angle ABC (it's just two adjoining 60° angles)
with center at B, draw a circle of radius 6.
Mark C where the circle intersects ray BC.
So now produce AB to P and construct a ⊥ from C to P.
Measure CP
To confirm your answer, it is clear that angle BCP = 60°
So CP = 6 sin60° = 3√3
Answered by
Prosper
Draw it for me
Answered by
Goodnews
Excellent
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