Question

An emergency flare is shot vertically into the air with a speed of 60m/s. It's height h metres after t seconds is given by the equation h=−5(t−6)2+180 What is the maximum height of the flare?

Answer 1

h =−5(t−6)^2+180 now complete the square
5 (t-6)^2 = 180 - h
(t-6)^2 = (1/5) (180-h)
vertex at t = 6 and h = 180

Answer 2

since the equation is written in vertex form, just read the maximum height from the equation.

Answer 3

how to solve it this h= -5(t-6)^2+180