Question

Given the functions ๐‘“(๐‘ฅ) = ๐‘™๐‘œ๐‘”_3 (3๐‘ฅ) and ๐‘”(๐‘ฅ) = ๐‘™๐‘œ๐‘”_3 (๐‘ฅ) + 1
a. Describe the transformations applied to each function.
b. How do the graphs of the two functions compare? Explain your answer by referring to logarithmic
laws and properties.

Answers

oobleck
log3(3x) = log3(3) + log3(x) = 1 + log3(x)
f(x) is identical to g(x)

g(x) is f(x)
dilated in x by 3
shifted up 1
The two transformations cancel each other out

the graphs of all exponential functions look the same
dilating and shifting are complementary operations.

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