Asked by Adedeji Bashiru
P, Q and R are point of a the same horizontal plane. The bearing of Q from P from P is 150° and the bearing of R from Q is 060°. If /PQ/ is 5m and /QR/ is 3m, find the bearing of R from P correct to nearest degree.
Answers
Answered by
oobleck
Draw a diagram. If we set Q at (0,0) then
P = (-5/2, 5/2√3)
R = (3,√3)
So the bearing of R from P is EθS such that
tanθ = (5-√3)/(3 + 5/2)
P = (-5/2, 5/2√3)
R = (3,√3)
So the bearing of R from P is EθS such that
tanθ = (5-√3)/(3 + 5/2)
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