Asked by Aman Verma

4x-3=log(x+1)+log 3
Answered by oobleck
4x-3 = log(3x+3)
This doesn't yield to algebraic solution, but any good calculator or numeric technique will get you (assuming logs base 10)
x ≈ 0.9413

now, if you meant to say
log(4x-3)=log(x+1)+log 3
then that means
4x-3 = 3x+3
x = 6
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