Question

An aeroplane flies due north from ikeja airport for 500km, it then flies on a bearing of 060 degree for a further distance of 300km before overflying a road junction. Calculate: the bearing of the aeroplane from ikeja airport at this instant

Answer 1

North 500 + 300 cos 60 = 650
East 300 sin 60 = 260
tan bearing from origin = East/North =260/650 = 0.4
bearing = 21.8 deg
By the way you fly on a heading, not a bearing. You take a bearing on something like a lighthouse or a plane. Math teachers do not fly airplanes or sail ships :)

Answer 2

the junction is
500+300cos60° = 650 km north
and 300 sin60° = 150√3 km east
so the bearing of the plane from the airport is θ, where
tanθ = 150√3/650
now use your calculator to find θ