Asked by Rebecca Gray
An explorer walks 50 km to the north and then 30 km west. What are the magnitude and direction of his displacement?
A. 58 km, 31 degrees West of North
B. 80 km, NorthWest
C. 58 km 31 degrees North of West
D. 3400 km, northwest
A. 58 km, 31 degrees West of North
B. 80 km, NorthWest
C. 58 km 31 degrees North of West
D. 3400 km, northwest
Answers
Answered by
oobleck
distance: √(50^2+30^2)
direction: θ° W of N where tanθ = 30/50
direction: θ° W of N where tanθ = 30/50
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