Asked by Telie
volume of a frustrum that measures 10*10m at the top and 16*16m at the bottom and is 12m high
Answers
Answered by
oobleck
V = 1/3 * (a2 + ab + b2)*h
so plug in your numbers
this makes sense if you recall that (a^3-b^3) = (a-b)(a2 + ab + b2)
so plug in your numbers
this makes sense if you recall that (a^3-b^3) = (a-b)(a2 + ab + b2)
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