Let 𝑓(𝑥)=5𝑔(𝑥)+3ℎ(𝑥)+2 such that 𝑔′(3)=4,ℎ′(3)=−1. Then 𝑓′(3) is

1 answer

f'(x) = 5g'(x) + 3h'(x)
so now plug in x=3