Asked by Joann
May someone help me differentiate the following
d/dx (2 x 3^k e^3x).
Thanks
d/dx (2 x 3^k e^3x).
Thanks
Answers
Answered by
oobleck
use the product rule. Since 3^k is just a constant,
d/dx (3^k * 2x e^(3x))
= 2*3^k d/dx (xe^(3x))
= 2*3^k (e^(3x) + x * 3e^(3x))
= 2*3^k e^(3x) (1+3x)
d/dx (3^k * 2x e^(3x))
= 2*3^k d/dx (xe^(3x))
= 2*3^k (e^(3x) + x * 3e^(3x))
= 2*3^k e^(3x) (1+3x)
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