Asked by Snojika

The mass (in grams) of FeSO4*7H2O required for preparation of 125 mL of 0.90 M
Answered by DrBob222
You want how many moles? That's mols = M x L = = 0.90 x 0.125 = ?
Then grams = mols x molar mass. You know mols and molar mass. Solve for grams. Post your work if you get stuck.
Answered by Biomy
Stuck
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