Asked by Kaur
Find domain and range of
F(x)= root(x^2+4x+3)
F(x)= root(x^2+4x+3)
Answers
Answered by
Anonymous
√x is defined only for x >= 0
So, you need x^2+4x+3 >= 0
That is x <= -3 or x >= 1
The domain is thus (-∞,-3]U[-1,∞)
since f(x) = (x+2)^2 -1
the range is [-1,∞)
So, you need x^2+4x+3 >= 0
That is x <= -3 or x >= 1
The domain is thus (-∞,-3]U[-1,∞)
since f(x) = (x+2)^2 -1
the range is [-1,∞)
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